3.2619 \(\int \frac {(2+3 x)^4}{(1-2 x)^{5/2} (3+5 x)^{3/2}} \, dx\)

Optimal. Leaf size=113 \[ \frac {7 (3 x+2)^3}{33 (1-2 x)^{3/2} \sqrt {5 x+3}}-\frac {1099 (3 x+2)^2}{726 \sqrt {1-2 x} \sqrt {5 x+3}}-\frac {\sqrt {1-2 x} (8200665 x+4898747)}{798600 \sqrt {5 x+3}}+\frac {4887 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{200 \sqrt {10}} \]

[Out]

4887/2000*arcsin(1/11*22^(1/2)*(3+5*x)^(1/2))*10^(1/2)+7/33*(2+3*x)^3/(1-2*x)^(3/2)/(3+5*x)^(1/2)-1099/726*(2+
3*x)^2/(1-2*x)^(1/2)/(3+5*x)^(1/2)-1/798600*(4898747+8200665*x)*(1-2*x)^(1/2)/(3+5*x)^(1/2)

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Rubi [A]  time = 0.03, antiderivative size = 113, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.192, Rules used = {98, 150, 143, 54, 216} \[ \frac {7 (3 x+2)^3}{33 (1-2 x)^{3/2} \sqrt {5 x+3}}-\frac {1099 (3 x+2)^2}{726 \sqrt {1-2 x} \sqrt {5 x+3}}-\frac {\sqrt {1-2 x} (8200665 x+4898747)}{798600 \sqrt {5 x+3}}+\frac {4887 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{200 \sqrt {10}} \]

Antiderivative was successfully verified.

[In]

Int[(2 + 3*x)^4/((1 - 2*x)^(5/2)*(3 + 5*x)^(3/2)),x]

[Out]

(-1099*(2 + 3*x)^2)/(726*Sqrt[1 - 2*x]*Sqrt[3 + 5*x]) + (7*(2 + 3*x)^3)/(33*(1 - 2*x)^(3/2)*Sqrt[3 + 5*x]) - (
Sqrt[1 - 2*x]*(4898747 + 8200665*x))/(798600*Sqrt[3 + 5*x]) + (4887*ArcSin[Sqrt[2/11]*Sqrt[3 + 5*x]])/(200*Sqr
t[10])

Rule 54

Int[1/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_.) + (d_.)*(x_)]), x_Symbol] :> Dist[2/Sqrt[b], Subst[Int[1/Sqrt[b*c -
a*d + d*x^2], x], x, Sqrt[a + b*x]], x] /; FreeQ[{a, b, c, d}, x] && GtQ[b*c - a*d, 0] && GtQ[b, 0]

Rule 98

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((b*c -
a*d)*(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^(p + 1))/(b*(b*e - a*f)*(m + 1)), x] + Dist[1/(b*(b*e - a*
f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 2)*(e + f*x)^p*Simp[a*d*(d*e*(n - 1) + c*f*(p + 1)) + b*c*(d
*e*(m - n + 2) - c*f*(m + p + 2)) + d*(a*d*f*(n + p) + b*(d*e*(m + 1) - c*f*(m + n + p + 1)))*x, x], x], x] /;
FreeQ[{a, b, c, d, e, f, p}, x] && LtQ[m, -1] && GtQ[n, 1] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p
] || IntegersQ[p, m + n])

Rule 143

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_) + (f_.)*(x_))*((g_.) + (h_.)*(x_)), x_Symbol] :
> Simp[((b^2*d*e*g - a^2*d*f*h*m - a*b*(d*(f*g + e*h) - c*f*h*(m + 1)) + b*f*h*(b*c - a*d)*(m + 1)*x)*(a + b*x
)^(m + 1)*(c + d*x)^(n + 1))/(b^2*d*(b*c - a*d)*(m + 1)), x] + Dist[(a*d*f*h*m + b*(d*(f*g + e*h) - c*f*h*(m +
2)))/(b^2*d), Int[(a + b*x)^(m + 1)*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, m, n}, x] && EqQ[m
+ n + 2, 0] && NeQ[m, -1] &&  !(SumSimplerQ[n, 1] &&  !SumSimplerQ[m, 1])

Rule 150

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[((b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^(p + 1))/(b*(b*e - a*f)*(m + 1)), x] - Dist[1
/(b*(b*e - a*f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[b*c*(f*g - e*h)*(m + 1) + (
b*g - a*h)*(d*e*n + c*f*(p + 1)) + d*(b*(f*g - e*h)*(m + 1) + f*(b*g - a*h)*(n + p + 1))*x, x], x], x] /; Free
Q[{a, b, c, d, e, f, g, h, p}, x] && LtQ[m, -1] && GtQ[n, 0] && IntegersQ[2*m, 2*n, 2*p]

Rule 216

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[(Rt[-b, 2]*x)/Sqrt[a]]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rubi steps

\begin {align*} \int \frac {(2+3 x)^4}{(1-2 x)^{5/2} (3+5 x)^{3/2}} \, dx &=\frac {7 (2+3 x)^3}{33 (1-2 x)^{3/2} \sqrt {3+5 x}}-\frac {1}{33} \int \frac {(2+3 x)^2 \left (148+\frac {507 x}{2}\right )}{(1-2 x)^{3/2} (3+5 x)^{3/2}} \, dx\\ &=-\frac {1099 (2+3 x)^2}{726 \sqrt {1-2 x} \sqrt {3+5 x}}+\frac {7 (2+3 x)^3}{33 (1-2 x)^{3/2} \sqrt {3+5 x}}-\frac {1}{363} \int \frac {\left (-\frac {14369}{2}-\frac {49701 x}{4}\right ) (2+3 x)}{\sqrt {1-2 x} (3+5 x)^{3/2}} \, dx\\ &=-\frac {1099 (2+3 x)^2}{726 \sqrt {1-2 x} \sqrt {3+5 x}}+\frac {7 (2+3 x)^3}{33 (1-2 x)^{3/2} \sqrt {3+5 x}}-\frac {\sqrt {1-2 x} (4898747+8200665 x)}{798600 \sqrt {3+5 x}}+\frac {4887}{400} \int \frac {1}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx\\ &=-\frac {1099 (2+3 x)^2}{726 \sqrt {1-2 x} \sqrt {3+5 x}}+\frac {7 (2+3 x)^3}{33 (1-2 x)^{3/2} \sqrt {3+5 x}}-\frac {\sqrt {1-2 x} (4898747+8200665 x)}{798600 \sqrt {3+5 x}}+\frac {4887 \operatorname {Subst}\left (\int \frac {1}{\sqrt {11-2 x^2}} \, dx,x,\sqrt {3+5 x}\right )}{200 \sqrt {5}}\\ &=-\frac {1099 (2+3 x)^2}{726 \sqrt {1-2 x} \sqrt {3+5 x}}+\frac {7 (2+3 x)^3}{33 (1-2 x)^{3/2} \sqrt {3+5 x}}-\frac {\sqrt {1-2 x} (4898747+8200665 x)}{798600 \sqrt {3+5 x}}+\frac {4887 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )}{200 \sqrt {10}}\\ \end {align*}

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Mathematica [A]  time = 0.10, size = 94, normalized size = 0.83 \[ \frac {10 \sqrt {2 x-1} \left (6468660 x^3-40488772 x^2-12657123 x+8379147\right )[phone] \sqrt {50 x+30} (1-2 x)^2 \sinh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {2 x-1}\right )}{7986000 \sqrt {1-2 x} (2 x-1)^{3/2} \sqrt {5 x+3}} \]

Antiderivative was successfully verified.

[In]

Integrate[(2 + 3*x)^4/((1 - 2*x)^(5/2)*(3 + 5*x)^(3/2)),x]

[Out]

(10*Sqrt[-1 + 2*x]*(8379147 - 12657123*x - 40488772*x^2 + 6468660*x^3) + 19513791*(1 - 2*x)^2*Sqrt[30 + 50*x]*
ArcSinh[Sqrt[5/11]*Sqrt[-1 + 2*x]])/(7986000*Sqrt[1 - 2*x]*(-1 + 2*x)^(3/2)*Sqrt[3 + 5*x])

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fricas [A]  time = 0.95, size = 106, normalized size = 0.94 \[ -\frac {19513791 \, \sqrt {10} {\left (20 \, x^{3} - 8 \, x^{2} - 7 \, x + 3\right )} \arctan \left (\frac {\sqrt {10} {\left (20 \, x + 1\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{20 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) + 20 \, {\left (6468660 \, x^{3} - 40488772 \, x^{2} - 12657123 \, x + 8379147\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{15972000 \, {\left (20 \, x^{3} - 8 \, x^{2} - 7 \, x + 3\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^4/(1-2*x)^(5/2)/(3+5*x)^(3/2),x, algorithm="fricas")

[Out]

-1/15972000*(19513791*sqrt(10)*(20*x^3 - 8*x^2 - 7*x + 3)*arctan(1/20*sqrt(10)*(20*x + 1)*sqrt(5*x + 3)*sqrt(-
2*x + 1)/(10*x^2 + x - 3)) + 20*(6468660*x^3 - 40488772*x^2 - 12657123*x + 8379147)*sqrt(5*x + 3)*sqrt(-2*x +
1))/(20*x^3 - 8*x^2 - 7*x + 3)

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giac [A]  time = 1.49, size = 131, normalized size = 1.16 \[ \frac {4887}{2000} \, \sqrt {10} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right ) - \frac {\sqrt {10} {\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}}{332750 \, \sqrt {5 \, x + 3}} - \frac {{\left (4 \, {\left (323433 \, \sqrt {5} {\left (5 \, x + 3\right )} - 13033138 \, \sqrt {5}\right )} {\left (5 \, x + 3\right )} + 214579893 \, \sqrt {5}\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5}}{99825000 \, {\left (2 \, x - 1\right )}^{2}} + \frac {2 \, \sqrt {10} \sqrt {5 \, x + 3}}{166375 \, {\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^4/(1-2*x)^(5/2)/(3+5*x)^(3/2),x, algorithm="giac")

[Out]

4887/2000*sqrt(10)*arcsin(1/11*sqrt(22)*sqrt(5*x + 3)) - 1/332750*sqrt(10)*(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)
)/sqrt(5*x + 3) - 1/99825000*(4*(323433*sqrt(5)*(5*x + 3) - 13033138*sqrt(5))*(5*x + 3) + 214579893*sqrt(5))*s
qrt(5*x + 3)*sqrt(-10*x + 5)/(2*x - 1)^2 + 2/166375*sqrt(10)*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)
)

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maple [A]  time = 0.02, size = 151, normalized size = 1.34 \[ \frac {\sqrt {-2 x +1}\, \left (390275820 \sqrt {10}\, x^{3} \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )-129373200 \sqrt {-10 x^{2}-x +3}\, x^{3}-156110328 \sqrt {10}\, x^{2} \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )[phone] \sqrt {-10 x^{2}-x +3}\, x^{2}-136596537 \sqrt {10}\, x \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )[phone] \sqrt {-10 x^{2}-x +3}\, x [phone] \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )-167582940 \sqrt {-10 x^{2}-x +3}\right )}{15972000 \left (2 x -1\right )^{2} \sqrt {-10 x^{2}-x +3}\, \sqrt {5 x +3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((3*x+2)^4/(-2*x+1)^(5/2)/(5*x+3)^(3/2),x)

[Out]

1/15972000*(-2*x+1)^(1/2)*(390275820*10^(1/2)*x^3*arcsin(20/11*x+1/11)-156110328*10^(1/2)*x^2*arcsin(20/11*x+1
/11)-129373200*(-10*x^2-x+3)^(1/2)*x^3-136596537*10^(1/2)*x*arcsin(20/11*x+1/11)[phone]*(-10*x^2-x+3)^(1/2)
*x^2+58541373*10^(1/2)*arcsin(20/11*x+1/11)[phone]*(-10*x^2-x+3)^(1/2)*x-167582940*(-10*x^2-x+3)^(1/2))/(2*
x-1)^2/(-10*x^2-x+3)^(1/2)/(5*x+3)^(1/2)

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maxima [A]  time = 1.35, size = 95, normalized size = 0.84 \[ \frac {4887}{4000} \, \sqrt {5} \sqrt {2} \arcsin \left (\frac {20}{11} \, x + \frac {1}{11}\right ) + \frac {81 \, x^{2}}{20 \, \sqrt {-10 \, x^{2} - x + 3}} - \frac {18627221 \, x}{798600 \, \sqrt {-10 \, x^{2} - x + 3}} - \frac {3910543}{199650 \, \sqrt {-10 \, x^{2} - x + 3}} - \frac {2401}{264 \, {\left (2 \, \sqrt {-10 \, x^{2} - x + 3} x - \sqrt {-10 \, x^{2} - x + 3}\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^4/(1-2*x)^(5/2)/(3+5*x)^(3/2),x, algorithm="maxima")

[Out]

4887/4000*sqrt(5)*sqrt(2)*arcsin(20/11*x + 1/11) + 81/20*x^2/sqrt(-10*x^2 - x + 3) - 18627221/798600*x/sqrt(-1
0*x^2 - x + 3) - 3910543/199650/sqrt(-10*x^2 - x + 3) - 2401/264/(2*sqrt(-10*x^2 - x + 3)*x - sqrt(-10*x^2 - x
+ 3))

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\left (3\,x+2\right )}^4}{{\left (1-2\,x\right )}^{5/2}\,{\left (5\,x+3\right )}^{3/2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((3*x + 2)^4/((1 - 2*x)^(5/2)*(5*x + 3)^(3/2)),x)

[Out]

int((3*x + 2)^4/((1 - 2*x)^(5/2)*(5*x + 3)^(3/2)), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)**4/(1-2*x)**(5/2)/(3+5*x)**(3/2),x)

[Out]

Timed out

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